5a^2=-25a

Solution for 5a^2=-25a equation:

5a^2=-25a

We move all terms to the left:

5a^2-(-25a)=0

We get rid of parentheses

5a^2+25a=0

a = 5; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·5·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*5}=\frac{-50}{10}
=-5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*5}=\frac{0}{10}
=0
$